4(x-3)^2+5=29

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Solution for 4(x-3)^2+5=29 equation: 



4(x-3)^2+5=29

We move all terms to the left:

4(x-3)^2+5-(29)=0

We add all the numbers together, and all the variables

4(x-3)^2-24=0

We move all terms containing x to the left, all other terms to the right

4(x-3)^2=24

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